Pb-Pb dating method

Dr. Ahmad Redaa

2024-10-19

Age Equation Using the Pb²⁰⁷/Pb²⁰⁶ Ratio

The age of a sample can also be determined by using the ratio of Pb²⁰⁷ to Pb²⁰⁶. Starting with the following decay equations for uranium isotopes:

Pb²⁰⁷ from U²³⁵ decay:

\[ ^{207}\text{Pb} = ^{235}\text{U} (e^{\lambda_{235} t} - 1) \]

Pb²⁰⁶ from U²³⁸ decay:

\[ ^{206}\text{Pb} = ^{238}\text{U} (e^{\lambda_{238} t} - 1) \]

By taking the ratio of these two equations, and knowing that the natural abundance ratio of \(^{235}\text{U}/^{238}\text{U}\) is approximately 1/137.8, we get:

\[ \frac{^{207}\text{Pb}}{^{206}\text{Pb}} = \frac{^{235}\text{U}}{^{238}\text{U}} \cdot \frac{(e^{\lambda_{235} t} - 1)}{(e^{\lambda_{238} t} - 1)} \]

Since \(\frac{^{235}\text{U}}{^{238}\text{U}} \approx \frac{1}{137.8}\), we can simplify the equation to:

\[ \frac{^{207}\text{Pb}}{^{206}\text{Pb}} = \frac{1}{137.8} \cdot \frac{(e^{\lambda_{235} t} - 1)}{(e^{\lambda_{238} t} - 1)} \]

Pb²⁰⁷/Pb²⁰⁶ Isotope Ratio and Its Use in Age Dating

Numerical Values of the Radiogenic Pb²⁰⁷/Pb²⁰⁶ Isotope Ratio Over Time

Time (Ga) \[(e^{\lambda_{238} t} - 1)\] \[(e^{\lambda_{235} t} - 1)\] Pb²⁰⁷/Pb²⁰⁶ Radiogenic
0.0 0.0000 0.0000 0.00000
0.2 0.0315 0.2177 0.05012
0.4 0.0640 0.4828 0.05471
0.6 0.0975 0.8056 0.05992
0.8 0.1321 1.1987 0.06581
1.0 0.1678 1.6774 0.07250
1.2 0.2046 2.2603 0.08012
1.4 0.2426 2.9701 0.08879
1.6 0.2817 3.8344 0.09872
1.8 0.3221 4.8869 0.11000
2.0 0.3638 6.1685 0.12298
2.2 0.4067 7.7292 0.13783
2.4 0.4511 9.6296 0.15482
2.6 0.4968 11.9437 0.17436
2.8 0.5440 14.7617 0.19680
3.0 0.5926 18.1931 0.22266
3.2 0.6428 22.3716 0.25241
3.4 0.6946 27.4597 0.28672
3.6 0.7480 33.6556 0.32634
3.8 0.8030 41.2004 0.37212
4.0 0.8599 50.3878 0.42498
4.2 0.9185 61.5752 0.48623
4.4 0.9789 75.1984 0.55714
4.6 1.0413 91.7873 0.63930

Key Points:

For example:
- At 0.2 Ga, the radiogenic Pb²⁰⁷/Pb²⁰⁶ ratio is 0.05012.
- At 2.0 Ga, the ratio is 0.12298.
- At 4.6 Ga (the approximate age of the Earth), the ratio is 0.63930.

Example

The Pb²⁰⁶/Pb²⁰⁷ ratio of a uranium ore deposit is found to be 13.50. What is the age of the ore, assuming it has remained closed since crystallization and common lead can be ignored?

Solution

  1. Given:

    • Measured ratio: \(\frac{^{206}\text{Pb}}{^{207}\text{Pb}} = 13.50\)
  2. Convert to Pb²⁰⁷/Pb²⁰⁶:

    • The inverse of the given ratio will give \(\frac{^{207}\text{Pb}}{^{206}\text{Pb}}\):

    \[ \frac{^{207}\text{Pb}}{^{206}\text{Pb}} = \frac{1}{13.50} = 0.07407 \]

  3. Compare with the Table:

    • From the table, find the value closest to \(\frac{^{207}\text{Pb}}{^{206}\text{Pb}} = 0.07407\).
    • At 1.0 Ga, \(\frac{^{207}\text{Pb}}{^{206}\text{Pb}} \approx 0.07250\).
    • At 1.2 Ga, \(\frac{^{207}\text{Pb}}{^{206}\text{Pb}} \approx 0.08012\).
  4. Interpolate:

    • To estimate the age between 1.0 Ga and 1.2 Ga, interpolate the values:

    \[ \text{Age} = 1.0 + \left( \frac{0.07407 - 0.07250}{0.08012 - 0.07250} \right) \times 0.2 \]

    \[ \text{Age} = 1.0 + \left( \frac{0.00157}{0.00762} \right) \times 0.2 \approx 1.041 \text{ Ga} \]